800x^2+635x+1=0

Solution for 800x^2+635x+1=0 equation:

800x^2+635x+1=0

a = 800; b = 635; c = +1;
Δ = b2-4ac
Δ = 6352-4·800·1
Δ = 400025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{400025}=\sqrt{25*16001}=\sqrt{25}*\sqrt{16001}=5\sqrt{16001}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(635)-5\sqrt{16001}}{2*800}=\frac{-635-5\sqrt{16001}}{1600}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(635)+5\sqrt{16001}}{2*800}=\frac{-635+5\sqrt{16001}}{1600}
$